# Extended Kalman filter example in R

Last week's post about the Kalman filter focused on the derivation of the algorithm. Today I will continue with the extended Kalman filter (EKF) that can deal also with nonlinearities. According to Wikipedia the EKF has been considered the de facto standard in the theory of nonlinear state estimation, navigation systems and GPS.### Kalman filter

I had the following dynamic linear model for the Kalman filter last week:\[\begin{align}

x_{t+1} & = A x_t + w_t,\quad w_t \sim N(0,Q)\\

y_t &=G x_t + \nu_t, \quad \nu_t \sim N(0,R)\\

x_1 & \sim N(\hat{x}_0, \Sigma_0)

\end{align}

\]With \(x_t\) describing the state space evolution, \(y_t\) the observations, \(A, Q, G, R, \Sigma_0\) matrices of appropriate dimensions, \(w_t\) the evolution error and \(\nu_t\) the observation error. The Kalman filter provides recursive estimators for \(x_t\) via:

\[\begin{align}

K_{t} &= A \Sigma_t G' (G \Sigma_t G' + R)^{-1}\\

\hat{x}_{t+1} &= A \hat{x_t} + K_{t} (y_t - G \hat{x}_t) \\

\Sigma_{t+1} &= A \Sigma_t A' - K_{t} G \Sigma_t A' + Q

\end{align}\]In the case of nonlinearities on the right hand side of either the state (\(x_t\)) or observation (\(y_t\)) equation the extended Kalman filter uses a simple and elegant trick: Taylor series of the first order, or in other words, I simply linearise the right hand side. The matrices \(A\) and \(G\) will be the Jacobian matrices of the respected vector functions.

### Logistic growth

As an example I will use a logistic growth model, inspired by the Hakell example given by Dominic Steinitz.The logistic growth model can be written as a time-invariant dynamical system with growth rate \(r\) and carrying capacity \(k\):

\[

\begin{aligned}

\dot{p} & = r p\Big(1 - \frac{p}{k}\Big)

\end{aligned}

\]The above ordinary differential equation has the well known analytical solution:

\[

p = \frac{kp_0\exp(r\,t)}{k + p_0(\exp(r\,t) - 1)}

\]Suppose I observe data of a population for which I know the carrying capacity \(k\), but where the growth rate \(r\) is noisy.

### Extended Kalman filter

The state space and observation model can then be written as:\[

\begin{aligned}

r_i &= r_{i-1} \\

p_i &= \frac{kp_{i-1}\exp(r_{i-1}\Delta T)}{k + p_{i-1}(\exp(r_{i-1}\Delta T) - 1)} \\

y_i &= \begin{bmatrix}0 & 1\end{bmatrix} \begin{bmatrix}r_i \\

p_i\end{bmatrix} + \nu

\end{aligned}

\]Or with \(x_i:=\begin{bmatrix}r_i & p_i\end{bmatrix}'\) as:

\[

\begin{aligned}

x_i &= a(x_i)\\

y_i &= G x_i + \nu_i, \quad \nu_i \sim N(0,R)

\end{aligned}

\]In my example the state space model is purely deterministic, so there isn't any evolution noise and hence \(Q=0\).

With an initial prior guess for \(x_0\) and \(\Sigma_0\) and I am ready to go. The R code below shows my implementation with the algorithm above. Note that I use the

`jacobian`

function of the `numDeriv`

package.After a few time steps the extended Kalman filter does a fantastic job in reducing the noise. Perhaps this shouldn't be too surprising as a local linearisation of the logistic growth function will give a good fit. The situation might be different for highly nonlinear functions. The Wikipedia article about the Kalman filter suggests the unscented version in those cases.

### R code

### Session Info

```
R version 3.1.2 (2014-10-31)
Platform: x86_64-apple-darwin13.4.0 (64-bit)
locale:
[1] en_GB.UTF-8/en_GB.UTF-8/en_GB.UTF-8/C/en_GB.UTF-8/en_GB.UTF-8
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] numDeriv_2012.9-1
loaded via a namespace (and not attached):
[1] tools_3.1.2
```

Subscribe to:
Post Comments
(
Atom
)

Hey I really enjoyed this blog post... I was wondering if you knew how to optimize this function if you didn't know the observations variance (R) parameter.

ReplyDeleteI tried a little bit of code to optimize this function assuming R was unknown but was getting values of 133 instead of 25. I used the likelihood function found here page 33 http://www.idsc.ethz.ch/Courses/stochasticsystems/Kalman_Filter.pdf.

If you could shed any light on where I'm going wrong or on how to optimize kalman filter parameters in non - linear framework, I'd appreciate it.

Again, great post!

Code I tried to Optimize R:

kalman.filter.function=function(R){

x <- c(r, p0)

Sigma <- diag(c(144, 25))

R=R

llik=rep(0,nObs)

for(i in 1:nObs){

# Observation

xobs <- c(0, pop[i])

y <- G %*% xobs

# Filter

SigTermInv <- solve(G %*% Sigma %*% t(G) + R)

xf <- x + Sigma %*% t(G) %*% SigTermInv %*% (y - G %*% x)

Sigma <- Sigma - Sigma %*% t(G) %*% SigTermInv %*% G %*% Sigma

A <- jacobian(a, x=x, k=k, deltaT=deltaT)

K <- A %*% Sigma %*% t(G) %*% solve(G %*% Sigma %*% t(G) + R)

Estimate[i,] <- x

# Predict

x <- a(x=xf, k=k, deltaT=deltaT) + K %*% (y - G %*% xf)

Sigma <- A %*% Sigma %*% t(A) - K %*% G %*% Sigma %*% t(A) + Q

llik[i]=log((K[2]))+ ((G %*% x-y)^2)/K[2]

}

return(sum(llik))

}

optim(1, kalman.filter.function,lower=(1e-6),method="L-BFGS-B")

Thanks for your comment. Unfortunately, I don't think I can help you out here quickly.

ReplyDeletePlease I will like to know if you can assist with some modification to the kalman filter state equation. I am considering the use of the smooth transition autoregressive model as the state equation in the kalman filter system

ReplyDeleteHi, I think that there are mistakes in your code, because you are first doing the filtering step (update) and then the prediction step, while its should be the other way around. First, one makes a prediction of the state and computes the Kalman gain matrix. After the observation is known, one propagates the error of the prediction to update the state distribution moments.

ReplyDelete